Previous - Measurement 1: Area and Perimeter

**Surface Area**

The surface area of a figure is the total area of all the sides of the figure.

**Triangular Prism (Right Angle Triangle)**

To find the surface area of the prism above, follow the steps below:

Divide the figure into smaller shapes, find the area of each smaller shape and then sum the areas of each smaller shape. A right-angle triangle prisim can be divided into five smaller shapes which are two right angle triangles and three rectangles.

**Example**

Find the surface area of the prism below.

Area of right angle triangle = 1/ 2 base x height = 1/ 2 x 4 x 3 = 6

As there are 2 of these right angle triangles, we have 6 x 2 = 12

Area of rectangle 1: 4 x 7= 28

Area of rectangle 2: 5 x 7= 35

Area of rectangle 3: 3 x 7= 21

Surface area = 12 + 28 + 35 + 21 = 96cm^{2}

**Pyramid**

A pyramid is a solid formed by connecting a polygonal base and a point, called the apex.

The surface area of a pyramid = Area of the base + 1/ 2 Perimeter of Base x Length of Side

**Example**

Find the surface area of the following pyramid

Surface area of pyramid = Area of base + 1/ 2 perimeter of base x length

Area of 6 x 6 = 36cm^{2}

Perimeter = 1/ 2 4(6) = 12cm

Surface area = 36 + 12 x 12 = 36 + 144 = 180 cm^{2}

**Cylinder**

A cylinder can be divided into three parts: two circles and a curved surface area.

So the surface area = 2πr^{2} + 2πrh

The first term is the area of the two circles and the second term is the perimeter of the cylinder.

**Example**

Find the surface area of a cylinder with a radius of 3 cm, and a height of 2 cm.

**Solution**

SA = 2 × π × r^{2} + 2 × π × r × h

SA = 2 × 3.14 × 3^{2} + 2 × 3.14 × 3 × 2

SA = 6.28 × 9 + 6.28 × 3 x 2

SA = 56.52 + 37.68

Surface area = 94.2 cm^{2}

**Cube**

A cube has 6 sides or faces of the same surface area. Therefore, if the area of a square is side times side, then the surface area is S times S times 6.

**Cuboid**

A ** cuboid** is an object with six flat faces and all angles are right angles with all its faces being rectangles.

The surface area of a cuboid, A = 2Lw + 2 Lh + 2wh

where,

L is the length of the cuboid

w is the width and

h is the height of the cuboid.

**Example**

Find the surface area of a cuboid with length of 5cm, width 6cm and height 7cm.

**Solution**

A = 2Lw + 2 Lh + 2wh

= 2 x 5 x 6 + 2 x 5 x 7 + 2 x 6 x 7

= 60 + 70 + 84

= 214cm^{2}

**Sphere**

A sphere is a three-dimensional object such as a ball or the globe with every point on the surface halfway from the center.

The surface area of a sphere, A = 4πr^{2}

where, r is the radius of the sphere.

**Example**

Find the surface area of a sphere with radius of 9cm.

**Solution**

Surface Area of a sphere, A = 4 πr^{2}

4 x 3.14 x 9 x 9 = 1018 cm^{2}

**Volume**

Volume is the amount of 3-dimensional space an object occupies.

__Cube__

The volume of a cube , V = L^{3}

where, L is the length of a side of the cube.

**Example**

The volume of a cube with side of 4cm = 4 x 4 x 4 = 64cm^{3}

**Cuboid**

The volume of a cuboid, V = Lwh

where, L is the length of the cuboid,

w is the width and h is the height of the cuboid.

**Sphere**

The volume of a sphere, V = 4/3 πr^{3}

where, r is the radius of the sphere.

**Example**

The volume of a sphere with radius of 7cm = 4/ 3 x 22/ 7 x 7 x 7 x 7 = 4/ 3 (22/ 7) 7x7x7 = 1436.9cm^{3}

**Triangular Prism (Right Angle Triangle)**

The volume of a triangular prism, V = Area of one of the triangles times length

= 1/ 2 base x height x length of the triangular prism

**Example**

Find the volume of a triangular prism with base of 6cm, length of 8cm and height of 7cm.

**Solution**

Volume = 1/ 2 (6) x 7 x 8

= 3 x 7 x 8 = 168cm^{3}

**Pyramid**

The volume of a pyramid = 1/ 3 Area x height.

**Example**

Find the volume of a pyramid with length of 9cm and height of 14cm.

**Solution**

V = 1/ 3 (9 x 9) x 14 =

= 27 x 14 = 378cm^{3}

**Cylinder**

The volume of a cylinder, V = πr^{2}h

where, πr^{2} is the area of the circular cross-section and h is the height of the cylinder.

**Example**

Find the volume of a cylinder with radius of 7 cm and height of 14cm.

**Solution**

Volume = 22/ 7 x 7 x 7 x 14

= 154 x 14 = 2155cm^{3}

**Distance, Speed and Time**

There are mathematical problems that require students to be able to calculate distance, time and speed.

Distance = Speed x Time

Time = Distance/Speed

Speed = Distance/Time

**Distance**

**Example**

Joe drove from his home to the mall at an average speed of 50 kilometres an hour and took 4 hours to do so. Calculate the distance from his home to the mall.

**Solution**

Distance = Speed x Time = 50 x 4 = 200 kilometres.

**Speed**

**Example**

Sherry walked to the park located 80 kilometers in 5 hours. Calculate her speed per hour.

Speed = Distance/Time = 80/5 = 16 kilometers per hour.

**Time**

A lady travelled a distance of 45 kilometers at a speed of 5 kilometers per hour. Calculate the time she took.

Speed = Distance/ Speed = 45/5 = 9 hours